Chemical Equilibrium || Le Chatelier's Principle || Lecture # 2 || Dr. Rizwana
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Kc changes with temperature because Kc is linked to ΔH; exothermic reactions (ΔH < 0) show decreasing Kc when temperature rises, while endothermic reactions (ΔH > 0) show increasing Kc when temperature rises.
Briefing
Chemical equilibrium constant (Kc) stays fixed against concentration, pressure, and catalyst changes only in specific ways—but temperature changes reliably shifts Kc. The lecture frames this through Le Chatelier’s principle: when a system at equilibrium is disturbed, the reaction shifts to counter the disturbance. Concentration and pressure adjustments change how much the system “wants” to react in the forward versus reverse direction, yet the equilibrium constant’s value remains tied to temperature, not to those other physical tweaks.
Temperature is the key exception. For an equilibrium reaction, Kc depends on temperature through the enthalpy change (ΔH). When ΔH is negative (an exothermic, “heat-evolving” reaction), increasing temperature drives Kc downward. The reason is practical: added heat effectively accelerates the backward (reverse) direction, pushing the system to consume products and reform reactants. When ΔH is positive (an endothermic, “heat-absorbing” reaction), increasing temperature raises Kc because the added thermal energy favors the forward direction, increasing the equilibrium amount of products.
Pressure changes are treated next using the ammonia synthesis example: nitrogen and hydrogen form ammonia, with stoichiometry that matters for gas-phase equilibria. The lecture emphasizes that applying pressure changes the effective “packing” of gas molecules in a confined volume. Le Chatelier’s principle then predicts a shift toward the side with fewer moles of gas, because that direction reduces the stress caused by compression. In the ammonia example, pressure favors the formation of ammonia when the forward reaction reduces the number of gas molecules relative to the reactant side. The equilibrium composition adjusts accordingly, but the equilibrium constant’s value is not presented as changing—rather, the system’s direction and rates adjust to minimize the applied pressure effect.
Concentration changes follow the same logic: if extra reactant or product is added, the system shifts to consume the added species and restore equilibrium. Using the nitrogen–hydrogen–ammonia setup again, adding more reactant (like hydrogen) pushes the reaction forward until the added concentration is consumed; removing product (like ammonia) similarly drives the reaction forward to replenish it. The lecture stresses that equilibrium is re-established only after the system consumes the “excess” concentration, meaning the forward and reverse rates rebalance again.
Catalysts are the final physical parameter. Catalysts do not change Kc. They lower activation energy, speeding up both forward and reverse reactions by providing an easier pathway, so equilibrium is reached faster but at the same equilibrium constant value. In short: temperature shifts Kc through ΔH; concentration and pressure shift equilibrium position to counter the disturbance; catalysts accelerate the approach to equilibrium without changing the equilibrium constant.
Cornell Notes
The equilibrium constant Kc depends on temperature and the reaction’s enthalpy change (ΔH), not on concentration, pressure, or catalysts. Increasing temperature decreases Kc for exothermic reactions (ΔH < 0) because it favors the reverse direction, while it increases Kc for endothermic reactions (ΔH > 0) by favoring the forward direction. Changing pressure shifts the equilibrium position in the gas-phase direction that reduces the number of moles of gas, illustrated with ammonia formation from nitrogen and hydrogen. Changing concentration shifts the reaction to consume added reactants or replace removed products until equilibrium is restored. Catalysts lower activation energy and speed up both directions equally, so Kc stays the same.
Why does changing temperature alter Kc, while changing concentration or pressure mainly shifts equilibrium position?
How does Le Chatelier’s principle predict the effect of pressure on ammonia synthesis?
What happens when extra reactant is added to a system already at equilibrium?
What happens if product is removed from an equilibrium mixture?
Why doesn’t a catalyst change Kc even though it speeds up reactions?
Review Questions
- If a reaction has ΔH < 0, what direction does increasing temperature push the equilibrium, and how should Kc change?
- In a gas-phase equilibrium, how does the number of moles of gas on each side determine the shift caused by increasing pressure?
- Why does adding a catalyst speed up reaching equilibrium without changing Kc?
Key Points
- 1
Kc changes with temperature because Kc is linked to ΔH; exothermic reactions (ΔH < 0) show decreasing Kc when temperature rises, while endothermic reactions (ΔH > 0) show increasing Kc when temperature rises.
- 2
Changing concentration shifts the equilibrium position to consume added reactants or replace removed products until equilibrium is restored.
- 3
Applying pressure shifts gas-phase equilibria toward the side with fewer moles of gas to reduce the stress caused by compression.
- 4
For pressure effects, the equilibrium composition changes, but Kc is treated as remaining governed by temperature.
- 5
Catalysts do not change Kc because they lower activation energy for both forward and reverse reactions equally.
- 6
Catalysts reduce the time required to reach equilibrium without altering the equilibrium constant value at a fixed temperature.