Chemical Kinetics || Lec # 3 || Zero Order Reaction || First Order Reaction || Dr. Rizwana
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Zero-order kinetics have rate = k, with no dependence on reactant concentration.
Briefing
Zero-order reactions are defined by a rate that does not depend on the concentration of the reactant. In practical terms, that means the rate law for a reactant A converting into products is constant: the rate equals k, and the concentration of A decreases linearly with time. The lecture derives this by starting from the rate as the negative change in reactant concentration over time, then setting up the proportionality constant k. Because the reaction is “zero order,” the concentration term in the rate expression effectively has an exponent of zero, so k carries the entire rate dependence.
To connect the math to measurable behavior, the lecture introduces the standard concentration-change setup: let x represent the amount of product formed after time t, so the concentration of A at time t becomes (a − x) when the initial concentration is a. Since x increases as time passes, the concentration of A falls accordingly. Solving the resulting differential relationship yields the zero-order integrated form in which x grows linearly with time, matching the expectation of a straight-line concentration–time relationship. The lecture also emphasizes units: for zero-order kinetics, k has units of mol dm⁻³ s⁻¹, consistent with rate being concentration per unit time.
Examples of zero-order behavior are given to anchor the concept in real chemistry. Decomposition of ammonia on a tungsten filament is cited as a zero-order example, and decomposition of hydrogen iodide into hydrogen and iodine on a gold surface is also presented as zero-order. These surface- and condition-dependent systems are typical places where the rate can become independent of bulk reactant concentration.
First-order reactions, by contrast, depend on the concentration of only one reactant. The lecture defines first-order kinetics as a rate law where the rate equals k[A], so the rate decreases as A is consumed. Using the same style of concentration tracking—x as product formed and (a − x) as remaining reactant concentration—the lecture shows that the rate is inversely tied to how much A remains. The differential equation rearranges into a logarithmic integrated form, producing the familiar relationship between time and reactant concentration: ln(a/(a − x)) is proportional to kt.
The lecture then turns to half-life, a key first-order concept. Half-life is the time required for the reactant concentration to drop to half its initial value. By substituting the condition that the remaining reactant is a/2, the lecture arrives at the standard result t₁/₂ = 0.693/k (with 0.693 coming from ln 2). It also notes that half-life can be used with any first-order reaction by plugging in the appropriate k value.
Finally, the lecture describes how first-order kinetics appear on plots. When ln[A] is plotted against time, the result is a straight line. The slope magnitude relates to k, and the sign of the slope reflects whether the logarithmic reactant term is decreasing over time. Thermal decomposition of H2O and N2O5 is listed as an example set for first-order behavior, with the lecture closing by previewing second- and third-order reactions for the next session.
Cornell Notes
Zero-order reactions have a constant rate that does not depend on reactant concentration: rate = k. As A is consumed, its concentration decreases linearly with time, and the concentration–time behavior matches a straight-line trend. The lecture derives the integrated relationship using x as the amount of product formed and (a − x) as the remaining reactant concentration, then highlights k’s units for zero order (mol dm⁻³ s⁻¹). For first-order reactions, the rate depends on one reactant concentration: rate = k[A]. Integrating the first-order rate law leads to a logarithmic form, and half-life becomes t₁/₂ = 0.693/k, with ln[A] vs time producing a straight line whose slope relates to k.
What does it mean for a reaction to be “zero order,” and how does that show up in the rate law?
How does the lecture connect the variables a, x, and time t to concentration changes?
Why does the unit of k differ between zero-order and first-order kinetics?
How is half-life defined in the lecture, and what is the first-order half-life formula?
What plot behavior signals first-order kinetics, according to the lecture?
Which example reactions are used to illustrate zero-order and first-order behavior?
Review Questions
- If a reaction’s rate is independent of [A], what order is it and what is the form of its rate law?
- For a first-order reaction with k = 0.10 s⁻¹, what is t₁/₂ using t₁/₂ = 0.693/k?
- What straight-line plot would you use to confirm first-order kinetics, and what does the slope represent?
Key Points
- 1
Zero-order kinetics have rate = k, with no dependence on reactant concentration.
- 2
For zero order, reactant concentration decreases linearly with time, consistent with a straight-line concentration–time relationship.
- 3
The lecture assigns zero-order k units as mol dm⁻³ s⁻¹.
- 4
First-order kinetics follow rate = k[A], so the rate decreases as A is consumed.
- 5
Integrating the first-order rate law produces a logarithmic relationship between time and reactant concentration.
- 6
First-order half-life is constant for a given k and equals t₁/₂ = 0.693/k.
- 7
A plot of ln[A] versus time yields a straight line for first-order reactions, with slope tied to k.