Get AI summaries of any video or article — Sign up free
Complex Analysis 17 | Complex Integration on Real Intervals [dark version] thumbnail

Complex Analysis 17 | Complex Integration on Real Intervals [dark version]

5 min read

Based on The Bright Side of Mathematics's video on YouTube. If you like this content, support the original creators by watching, liking and subscribing to their content.

TL;DR

Define ∫_A^B γ(t) dt for continuous γ: [A,B] → ℂ by integrating Re(γ) and Im(γ) separately as ordinary Riemann integrals.

Briefing

Complex integration on real intervals sets up the machinery for integrating complex-valued functions by reducing everything to ordinary real Riemann integration. The core move is to define an integral of a complex function along a continuous map from a real interval [A, B] into the complex plane: if γ is continuous and complex-valued, then the complex integral is built from the real and imaginary parts separately. Concretely, the integral over γ is computed as the real Riemann integral of Re(γ) plus i times the real Riemann integral of Im(γ). This makes the definition well-posed for continuous γ and preserves familiar algebraic rules like linearity.

A key limitation also emerges immediately: unlike real integrals, complex numbers have no natural order, so “monotonicity” cannot carry over. Instead, the course replaces it with an inequality controlled by absolute values. The central estimate is that the magnitude of a complex integral is bounded by the integral of the magnitude of the integrand: |∫_A^B γ(t) dt| ≤ ∫_A^B |γ(t)| dt. This estimate becomes a foundational tool for later results, especially once integration moves from real intervals to arbitrary curves in the complex plane.

To make the definition feel concrete, the transcript works through an example using the unit circle. Take γ(t) = e^{it} on t ∈ [A, B]. Splitting into components gives Re(e^{it}) = cos t and Im(e^{it}) = sin t, so the complex integral becomes ∫_A^B cos t dt + i∫_A^B sin t dt. Using the fundamental theorem of calculus, the antiderivatives are sin t and −cos t, respectively. After simplifying, the result collapses back into a compact exponential form: ∫_A^B e^{it} dt = (1/i)(e^{iB} − e^{iA}), matching the idea that the fundamental theorem of calculus works in this complex setting just as it does for real integrals.

The proof of the absolute-value estimate is where the method really matters. The argument introduces w = ∫_A^B γ(t) dt and normalizes it by its magnitude: if w ≠ 0, define C = w/|w|, which lies on the unit circle so |C| = 1. Multiplying the integral by C^{-1} turns the complex number w into a positive real number |w|, allowing the real-part machinery to take over. Linearity lets C^{-1} move inside the integral, and then the inequality |Re(z)| ≤ |z| for any complex z bounds the integrand’s real part by its modulus. Monotonicity of the ordinary real Riemann integral applies to this real inequality, yielding |∫_A^B γ(t) dt| ≤ ∫_A^B |γ(t)| dt. The equality case aligns with the normalization choice.

With this real-interval complex integral in place—and with the absolute-value bound established—many familiar calculus tools are expected to transfer from the real Riemann setting: the fundamental theorem of calculus, substitution, and integration by parts. The next step is to extend these ideas from real intervals to curve integrals along general paths in the complex plane (the contour/line integral framework).

Cornell Notes

Complex integration over real intervals defines ∫_A^B γ(t) dt for a continuous complex-valued map γ by splitting it into real and imaginary parts: ∫ Re(γ(t)) dt + i∫ Im(γ(t)) dt, using ordinary Riemann integrals. This preserves linearity and makes the fundamental theorem of calculus work in the same way as for real integrals. A major difference is the lack of order in ℂ, so monotonicity is replaced by an absolute-value estimate: |∫_A^B γ(t) dt| ≤ ∫_A^B |γ(t)| dt. The proof normalizes the integral by its magnitude so the result becomes real, then applies |Re(z)| ≤ |z| and monotonicity for real Riemann integrals. This estimate becomes a key tool for later curve (contour) integrals.

How is the complex integral over a real interval defined for a continuous map γ: [A,B] → ℂ?

Write γ(t) = Re(γ(t)) + i Im(γ(t)). The complex integral is defined by integrating the components separately using ordinary Riemann integrals: ∫_A^B γ(t) dt := ∫_A^B Re(γ(t)) dt + i∫_A^B Im(γ(t)) dt. Continuity of γ ensures both component functions are continuous, so the real Riemann integrals exist.

Why does the fundamental theorem of calculus still work for this complex integral?

Because differentiation and antiderivatives can be applied componentwise. For example, with γ(t) = e^{it}, Re(e^{it}) = cos t and Im(e^{it}) = sin t. Antiderivatives are sin t for cos t and −cos t for sin t, so ∫_A^B e^{it} dt becomes sin t|_A^B + i(−cos t)|_A^B, which simplifies back to (1/i)(e^{iB} − e^{iA}). The same componentwise logic supports the fundamental theorem for complex-valued integrands.

What replaces monotonicity when moving from real integrals to complex integrals?

Complex numbers lack a natural order, so monotonicity cannot be stated. Instead, the course uses an absolute-value bound: |∫_A^B γ(t) dt| ≤ ∫_A^B |γ(t)| dt. This inequality plays the role of a control estimate that remains valid in ℂ.

How does the proof of |∫ γ| ≤ ∫ |γ| work?

Let w = ∫_A^B γ(t) dt. If w ≠ 0, define C = w/|w| so |C| = 1 (C lies on the unit circle). Then C^{-1}w = |w| is real and positive. By linearity, C^{-1} can be pulled inside the integral, turning the problem into bounding the real part of an integral. Using |Re(z)| ≤ |z| for all complex z, the real integrand is bounded by |γ(t)|, and monotonicity of the ordinary real Riemann integral yields the desired inequality.

What does the unit-circle example demonstrate about complex integration?

It shows that integrating e^{it} over [A,B] behaves like integrating a real function plus i times another real function. Splitting into cos t and sin t makes the computation straightforward with standard antiderivatives, and the final answer recombines into an exponential expression, reinforcing that familiar calculus rules extend naturally to complex-valued integrals.

Review Questions

  1. Given γ(t)=u(t)+iv(t) with u and v continuous, write the definition of ∫_A^B γ(t) dt in terms of u and v.
  2. State and interpret the inequality that bounds the magnitude of a complex integral by an integral of absolute values.
  3. Outline the normalization step (using C = w/|w|) used to prove the absolute-value estimate.

Key Points

  1. 1

    Define ∫_A^B γ(t) dt for continuous γ: [A,B] → ℂ by integrating Re(γ) and Im(γ) separately as ordinary Riemann integrals.

  2. 2

    The complex integral preserves linearity, allowing scalars and sums to be handled as in the real case.

  3. 3

    Because ℂ has no order, monotonicity is replaced by an absolute-value estimate for complex integrals.

  4. 4

    The fundamental estimate is |∫_A^B γ(t) dt| ≤ ∫_A^B |γ(t)| dt, which becomes a recurring tool.

  5. 5

    The unit-circle example γ(t)=e^{it} shows componentwise integration leads to a closed-form exponential result.

  6. 6

    The fundamental theorem of calculus extends to this complex integral by applying it to real and imaginary parts separately.

  7. 7

    The next conceptual step is extending from real-interval integrals to curve (contour/line) integrals in the complex plane.

Highlights

Complex integration over [A,B] is built from two ordinary Riemann integrals: one for Re(γ) and one for Im(γ).
The inequality |∫_A^B γ(t) dt| ≤ ∫_A^B |γ(t)| dt replaces real monotonicity and provides essential control.
For γ(t)=e^{it}, splitting into cos t and sin t lets the integral simplify back into an exponential form.
A normalization trick—multiplying by C^{-1} where C = w/|w|—turns a complex integral into a real quantity to enable the bound.

Topics

  • Complex Integration
  • Complex-Valued Integrals
  • Riemann Integrals
  • Absolute Value Estimate
  • Unit Circle Example