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Functional Analysis 26 | Open Mapping Theorem [dark version] thumbnail

Functional Analysis 26 | Open Mapping Theorem [dark version]

5 min read

Based on The Bright Side of Mathematics's video on YouTube. If you like this content, support the original creators by watching, liking and subscribing to their content.

TL;DR

An open map sends every open set in the domain to an open set in the codomain, with openness measured using the respective metrics.

Briefing

The open mapping theorem turns a structural property of linear operators into a topological guarantee: a bounded linear map between Banach spaces sends open sets to open sets exactly when it is surjective. That equivalence matters because “openness” is a strong, usable form of regularity—once it holds, it forces solutions to behave stably under perturbations and underlies many existence-and-uniqueness arguments in analysis.

An open map is defined for metric spaces X and Y: a function F: X → Y is open if for every open set A ⊆ X, the image F(A) is open in Y (with openness understood relative to the metrics on each space). This definition mirrors the logic of continuity—open sets on the input side correspond to open sets on the output side—but it runs in the opposite direction from continuity’s usual “preimage of open is open” condition.

A key example comes from bijections with continuous inverses. If F: X → Y is bijective and its inverse F^{-1}: Y → X is continuous, then F is open. The reason is direct from the definitions: continuity of F^{-1} ensures that whenever B ⊆ Y is open, its preimage (F^{-1})^{-1}(B) = F(B) is open in Y. This example highlights the practical intuition: when a map can be undone continuously, it also preserves the “openness” of sets.

Concrete functions on the real line illustrate what can go right or wrong. The map f(x) = x^3 from R to R is an open map because it is bijective and its inverse is continuous. By contrast, f(x) = x^2 is not an open map. Although it is continuous, it fails surjectivity and injectivity: applying it to the open interval (−2, 2) yields the image (0, 4), which is not open in R because it includes no negative values and does not extend beyond 0. The example shows that continuity alone does not guarantee openness.

With the notion of open maps in place, the open mapping theorem (also called the Banach–Schauder theorem) gives the central result. For a bounded linear operator T between Banach spaces, T is surjective if and only if T is an open map. Completeness of the spaces is essential: the theorem is not just about linearity and boundedness, but about the Banach-space setting where the topology and the operator theory align. The “easy” direction is that surjectivity implies openness; the nontrivial work lies in proving that if T is open, then it must be surjective. The theorem’s power is that it upgrades a linear bounded operator’s surjectivity into a strong topological statement about how it transforms neighborhoods.

A major downstream consequence is the bounded inverse theorem, foreshadowed as the next topic—an application that becomes routine in many areas of functional analysis and differential equations, where one needs not only existence of inverses but control over their boundedness and continuity.

Cornell Notes

The open mapping theorem links surjectivity of bounded linear operators to a topological property: openness. For metric spaces, a map is open if it sends every open set to an open set (openness is measured using the target metric). In Banach spaces, a bounded linear operator T is surjective exactly when it is an open map. This equivalence is valuable because it turns “onto” information into a guarantee that images of neighborhoods remain neighborhoods, which supports stability and solvability arguments. The theorem’s Banach-space assumption (completeness) is crucial; without it, the correspondence between linear operator behavior and openness can fail.

What does it mean for a function between metric spaces to be an open map, and how is that different from continuity?

For metric spaces X and Y, a map F: X → Y is open if for every open set A ⊆ X, the image F(A) is open in Y. Continuity is different: it requires that the preimage of every open set in Y is open in X. So openness tracks images of open sets, while continuity tracks preimages of open sets.

Why does a bijection with a continuous inverse automatically become an open map?

If F is bijective and F^{-1}: Y → X is continuous, then for any open set B ⊆ Y, continuity gives that (F^{-1})^{-1}(B) is open in X. But (F^{-1})^{-1}(B) equals F(B) because F and F^{-1} undo each other. Therefore F sends open sets B in Y to open sets in Y, making F an open map.

How do the examples f(x)=x^3 and f(x)=x^2 on R illustrate openness?

For f(x)=x^3, the map is bijective and its inverse is continuous, so it is open: images of open intervals remain open intervals in R. For f(x)=x^2, the map is not open: applying it to the open interval (−2,2) gives (0,4), which is not open in R because it does not include negative values and does not extend past 0.

What is the statement of the open mapping theorem for bounded linear operators?

For a bounded linear operator T between Banach spaces, T is surjective if and only if T is an open map. Completeness of both domain and codomain (the Banach-space condition) is essential for the equivalence to hold.

Why is the Banach-space assumption important in the open mapping theorem?

The theorem relies on completeness to ensure the topological and analytic structure needed for the equivalence. The openness/surjectivity relationship is not guaranteed in general metric spaces; the Banach setting provides the framework where bounded linear operators behave predictably enough for the theorem to work.

Review Questions

  1. Define an open map between metric spaces and contrast it with continuity using preimages vs images.
  2. State the open mapping theorem precisely, including the role of Banach spaces and bounded linear operators.
  3. Explain, using the real-line examples, why continuity does not imply openness (reference x^2 vs x^3).

Key Points

  1. 1

    An open map sends every open set in the domain to an open set in the codomain, with openness measured using the respective metrics.

  2. 2

    Openness is conceptually different from continuity: continuity uses preimages of open sets, while openness uses images of open sets.

  3. 3

    A bijection whose inverse is continuous is automatically an open map.

  4. 4

    On R, x^3 is open because it is bijective with continuous inverse, while x^2 is not open because it maps (−2,2) to (0,4), which is not open in R.

  5. 5

    The open mapping theorem (Banach–Schauder) says a bounded linear operator between Banach spaces is surjective exactly when it is an open map.

  6. 6

    Completeness (Banach-space structure) is essential for the surjectivity–openness equivalence to hold.

  7. 7

    The bounded inverse theorem is presented as a key consequence that follows from the open mapping theorem.

Highlights

Open maps preserve openness by sending open sets to open sets—unlike continuity, which preserves openness via preimages.
A continuous inverse turns a bijection into an open map, making openness a natural partner to invertibility.
The map x^2 on R fails to be open: (−2,2) becomes (0,4), which is not open in R.
For bounded linear operators between Banach spaces, surjectivity and openness are equivalent.
The Banach-space (completeness) requirement is not optional; it underpins the theorem’s validity.

Topics

  • Open Mapping Theorem
  • Open Maps
  • Banach Spaces
  • Bounded Linear Operators
  • Bounded Inverse Theorem