Functional Analysis 3 | Open and Closed Sets [dark version]
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An open ball B(x,ε) in a metric space X is the set of points y with d(x,y) < ε.
Briefing
Metric spaces generalize the familiar idea of “balls” around a point, and that single geometric object drives the definitions of open sets, boundary points, closed sets, and closure. An open ball centered at x with radius ε is the set of all points y in X whose distance from x is less than ε. Using these balls, a subset A of a metric space X is called open if every point x in A has some ε>0 such that the entire ε-ball around x stays inside A—meaning points in A never sit right up against a “border” where nearby points fall outside the set.
Boundary points formalize what it means to be on that border. A point x in X is a boundary point of A if every ε-ball around x contains at least one point from A and at least one point from the complement of A (X\A). Boundary points can lie inside A or outside A; what matters is that no matter how small the neighborhood gets, it straddles membership and non-membership. The collection of all boundary points is denoted ∂A. With this, openness and closedness become mirror conditions: A is open exactly when none of its boundary points lie in A (equivalently, ∂A ⊆ X\A). A set A is closed when its complement X\A is open, which matches the intuition that all boundary points of A must belong to A.
The last key notion is closure, written as \bar{A}. Starting from any subset A, its closure is obtained by adding all boundary points: \bar{A} = A ∪ ∂A. This construction always produces a closed set, and it is the smallest closed set that still contains A—so closure is the “minimal completion” needed to capture limit/border behavior.
Concrete examples in the real line (with the usual distance metric) make the definitions operational. Let X be the set of real numbers between 1 and 3 (including 3) together with all real numbers larger than 4. Consider A = [1,3]. Points strictly less than 3 can fit inside an ε-ball that stays within A, but the point 3 needs care because the surrounding space in X is missing the interval (3,4). Even so, choosing ε small enough ensures the ε-ball around 3 does not reach any points outside A that exist in X, so A is both open and closed in this particular universe X. The same universe-dependent effect explains why openness depends on knowing the ambient space X: the ε-ball around 3 is “one-sided” because points between 3 and 4 are not in X.
A second example uses C = {x in X : 1 ≤ x ≤ 2} with 2 included (in the transcript’s notation, C = [1,2] inside the chosen X). For points below 2, small ε-balls remain entirely within C, so they are not boundary points. At x=2, every ε-ball intersects both C (to the left) and X\C (to the right), so the boundary is ∂C = {2}. Since C already contains its boundary, its closure equals C itself, making C closed. The takeaway is that open/closed/closure are not absolute labels; they are determined by how a set sits inside its metric space and by which points its neighborhoods inevitably touch.
Cornell Notes
Open balls in a metric space X—points y with d(x,y) < ε—are the building blocks for defining openness and closedness. A set A ⊆ X is open if every point x in A has some ε-ball fully contained in A; boundary points are those where every ε-ball hits both A and X\A. The boundary ∂A can lie inside A or outside A, and it depends on the ambient space X. A set is closed when its complement is open (equivalently, when all boundary points of A lie in A). The closure \bar{A} = A ∪ ∂A always yields a closed set and is the smallest closed set containing A.
How does an ε-ball determine whether a point is “safe” inside an open set?
What exactly makes a point a boundary point of A?
Why can a set be both open and closed in the same metric space?
How is closure \bar{A} constructed, and why is it always closed?
In the example C = [1,2] (within the chosen X), why is the boundary only {2}?
Review Questions
- In a metric space X, what condition on ε-balls distinguishes an open set from a set that has boundary points inside it?
- Given a subset A ⊆ X, how do you compute ∂A and then form the closure \bar{A}?
- Why does the ambient space X affect whether a particular subset is open or closed?
Key Points
- 1
An open ball B(x,ε) in a metric space X is the set of points y with d(x,y) < ε.
- 2
A subset A ⊆ X is open if every x ∈ A has some ε>0 with B(x,ε) ⊆ A.
- 3
A point x is a boundary point of A if every ε-ball around x intersects both A and X\A; the boundary set is ∂A.
- 4
A set A is closed exactly when its complement X\A is open, which corresponds to requiring ∂A ⊆ A.
- 5
The closure of A is \bar{A} = A ∪ ∂A; it is always closed and is the smallest closed set containing A.
- 6
Openness and closedness are relative to the ambient metric space X, so missing points in X can make a set both open and closed.