Hilbert Spaces 2 | Examples of Hilbert Spaces [dark version]
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A Hilbert space is a complete inner product space: completeness is essential in infinite dimensions.
Briefing
Hilbert spaces are built from vector spaces plus an inner product, and the key practical takeaway is that many familiar “function” and “sequence” settings become Hilbert spaces once the right notion of completeness and inner-product geometry is in place. The construction matters because it turns abstract linear algebra ideas—like norms, orthogonality, and convergence—into a consistent framework for both finite and infinite-dimensional problems.
A Hilbert space is defined as a complete inner product space: start with a vector space X over a field F (either ℝ or ℂ), equip it with an inner product ⟨·,·⟩ that is positive definite, linear in the second argument, and conjugate symmetric, and then define the induced norm by \|x\| = sqrt(⟨x,x⟩). Completeness refers to the fact that every Cauchy sequence in the induced norm converges within the space. In finite dimensions, completeness is automatic, which is why the series shifts attention to infinite-dimensional examples where completeness is nontrivial.
The first major examples come from standard linear algebra. On ℂ^N (and similarly on ℝ^N), choosing the usual inner product gives a Hilbert space; the same remains true if one uses other valid inner products. The infinite-dimensional story begins with sequence spaces: \ell^2, the space of square-summable sequences (x_n) with \sum_{n=1}^\infty |x_n|^2 < ∞. For complex sequences, the inner product is defined by \langle y,x\rangle = \sum_{n=1}^\infty \overline{y_n} x_n, and convergence of this series is guaranteed via Hölder’s inequality. This is the infinite-dimensional analogue of the familiar dot product on finite vectors.
The construction then generalizes from sequences to functions using measure theory. Given a measure space (Ω, A, μ), one forms L^2(Ω) as the set of measurable functions f: Ω → ℂ that satisfy \int_Ω |f|^2 dμ < ∞. The induced “norm candidate” \sqrt{\int_Ω |f|^2 dμ} can fail to be a true norm because distinct functions can have integral zero (for instance, functions that differ only on sets of measure zero). The fix is to quotient out those problematic functions: define N as the set of functions with zero norm, and form the quotient space L^2 / N. Elements are equivalence classes, where two functions are equivalent if their difference lies in N. On these equivalence classes, the norm becomes well-defined and positive definite.
With the quotient in place, an inner product is defined on equivalence classes by integrating the product of representatives: \langle g,f\rangle = \int_Ω \overline{g} f\, dμ. This yields a genuine Hilbert space, including the classic case L^2(ℝ) with respect to Lebesgue measure. The payoff is conceptual: Hilbert spaces provide a geometry from inner products, making notions like orthogonality meaningful even in highly abstract settings—setting up the next step in the series.
Cornell Notes
Hilbert spaces are complete inner product spaces: a vector space X over ℝ or ℂ with an inner product ⟨·,·⟩ that is positive definite, linear in the second argument, and conjugate symmetric, together with the induced norm \|x\| = sqrt(⟨x,x⟩). Finite-dimensional spaces are automatically complete, so the focus shifts to infinite-dimensional examples.
The sequence space \ell^2 consists of square-summable sequences (x_n) with \sum_{n=1}^\infty |x_n|^2 < ∞, and it becomes a Hilbert space using the inner product \langle y,x\rangle = \sum_{n=1}^\infty \overline{y_n} x_n. For general measure spaces (Ω, A, μ), the function space L^2(Ω) uses the condition \int_Ω |f|^2 dμ < ∞, but a quotient is required because functions that differ only on measure-zero sets can have “norm” zero. After quotienting by those zero-norm functions, the inner product \int_Ω \overline{g} f\, dμ becomes well-defined, yielding a Hilbert space and enabling orthogonality in abstract settings.
Why does L^2(Ω) require a quotient construction instead of using the integral-based formula as a norm directly?
How does the inner product on \ell^2 mirror the standard dot product, and what ensures the infinite sum converges?
What changes when moving from ℂ^N to infinite-dimensional Hilbert spaces?
How is orthogonality made possible in these abstract Hilbert spaces?
Why does conjugation appear in the inner product for complex vector spaces?
Review Questions
- What properties must an inner product satisfy (including linearity/conjugation) for a space to qualify as an inner product space?
- Explain the role of measure-zero sets in the definition of L^2(Ω) and why quotienting is necessary.
- Write down the inner product formulas for \ell^2 and for L^2(Ω), and state what changes between them.
Key Points
- 1
A Hilbert space is a complete inner product space: completeness is essential in infinite dimensions.
- 2
The norm in a Hilbert space is determined by the inner product via \|x\| = sqrt(⟨x,x⟩).
- 3
Finite-dimensional inner product spaces are automatically complete, so infinite-dimensional examples drive the real work.
- 4
\ell^2 consists of square-summable sequences and becomes a Hilbert space using \langle y,x\rangle = \sum_{n=1}^\infty \overline{y_n} x_n.
- 5
For L^2(Ω), square-integrability means \int_Ω |f|^2 dμ < ∞, but the integral-based expression can yield zero for nonzero functions.
- 6
Quotienting by functions with zero integral (modulo measure-zero differences) fixes the norm and makes the inner product well-defined.
- 7
Once the inner product is established, geometry follows—especially orthogonality defined by zero inner product.