Manifolds 11 | Projective Space is a Manifold [dark version]
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Real projective space P^n\mathbb{R} is the quotient of S^n by the identification x \sim -x, with topology induced by the quotient map Q.
Briefing
Real projective space P^n\mathbb{R} is shown to be a well-defined n-dimensional manifold by building an explicit atlas from the sphere S^n and the standard identification x \sim -x. The construction starts with the quotient map Q: S^n \to P^n\mathbb{R}, sending each point to its equivalence class. Two points on the sphere represent the same projective point exactly when they are antipodal, so the topology on P^n\mathbb{R} is the quotient topology induced by Q.
To prove manifold structure, the key move is to cover P^n\mathbb{R} with n+1 open sets that correspond to where a chosen homogeneous coordinate is nonzero. For each i = 1,\dots,n+1, define V_i \subset P^n\mathbb{R} as the set of equivalence classes [x] for which the i-th coordinate of x is not zero. Because Q^{-1}(V_i) consists of points on S^n where x_i \neq 0, it becomes a union of two open hemispheres on the sphere (the regions where x_i is positive or negative). Since those preimages are open in S^n and the topology is quotient, each V_i is open in P^n\mathbb{R}. Together, the V_i cover all of P^n\mathbb{R} because every point on the sphere has at least one nonzero coordinate.
The atlas then comes from charts H_i that turn each V_i into Euclidean space. The transcript illustrates the idea first for n=1, where P^1\mathbb{R} can be visualized as lines through the origin in the plane. On the circle S^1, the chart domain V_1 corresponds to lines excluding the one where x_1=0; the chart uses slope as the coordinate. For a point on the sphere with x_1 \neq 0, the slope is x_2/x_1, and this ratio is well-defined on equivalence classes because flipping x \mapsto -x cancels the sign. The chart map is bijective onto an open subset of \mathbb{R}, and its inverse is built by taking the vector (1, m), scaling it to lie on the unit circle, and then passing to its equivalence class. Continuity of both directions yields a homeomorphism, establishing local Euclidean behavior.
For general n, the same mechanism scales up: each chart H_i maps an equivalence class [x] (with x_i \neq 0) to a vector in \mathbb{R}^n by dividing every coordinate by x_i and omitting the i-th slot. Concretely, the image is (x_1/x_i, \dots, x_{i-1}/x_i, x_{i+1}/x_i, \dots, x_{n+1}/x_i), producing an n-component vector. The normalization ensures the representative lies on S^n, and the inverse is constructed by inserting a 1 in the i-th position and scaling back to the sphere before taking the equivalence class. Each (V_i, H_i) therefore provides a homeomorphism with \mathbb{R}^n, so P^n\mathbb{R} is locally Euclidean of dimension n.
With this atlas in place—and using standard background properties like second countability and the Hausdorff condition—the result is that real projective space is a bona fide n-dimensional manifold. The next step, hinted for a later installment, is adding differentiability structure to these manifolds.
Cornell Notes
Real projective space P^n\mathbb{R} is built from the sphere S^n by identifying antipodal points x \sim -x. The quotient map Q: S^n \to P^n\mathbb{R} induces the quotient topology, and the space is covered by n+1 open sets V_i consisting of classes where the i-th homogeneous coordinate is nonzero. On each V_i, a chart H_i sends a class [x] to an n-tuple obtained by dividing all coordinates by x_i and omitting the i-th entry; this produces a homeomorphism from V_i to \mathbb{R}^n. The n=1 case uses slope of lines through the origin as the coordinate, with an inverse built by scaling (1,m) back to the unit circle. Together, these charts show P^n\mathbb{R} is an n-dimensional manifold.
How are points in real projective space identified, and what role does the quotient map play?
Why do the sets V_i form an open cover of P^n\mathbb{R}?
In the n=1 case, how does the chart coordinate arise, and why is it well-defined on equivalence classes?
What is the general formula for the chart H_i on V_i when n is arbitrary?
How is the inverse of H_i constructed in the general case?
Review Questions
- What are the definitions of V_i and H_i, and how do they depend on the condition x_i \neq 0?
- Why does the ratio x_j/x_i define a coordinate on equivalence classes under x \sim -x?
- How does the inverse chart construction ensure the representative lies on S^n before passing to the quotient?
Key Points
- 1
Real projective space P^n\mathbb{R} is the quotient of S^n by the identification x \sim -x, with topology induced by the quotient map Q.
- 2
Open sets V_i are defined by requiring the i-th homogeneous coordinate to be nonzero; their preimages on S^n split into two open hemispheres (x_i>0 and x_i<0).
- 3
The sets V_i cover P^n\mathbb{R} because every point on S^n has at least one nonzero coordinate.
- 4
Each chart H_i maps V_i to \mathbb{R}^n by dividing all coordinates by x_i and omitting the i-th entry, producing an n-tuple of ratios.
- 5
The coordinate functions are well-defined on equivalence classes because the sign flip x \mapsto -x cancels in the ratios.
- 6
For n=1, the chart coordinate becomes the slope x_2/x_1 of a line through the origin, with an inverse built by scaling (1,m) back to S^1.
- 7
Homeomorphisms from each V_i to \mathbb{R}^n establish that P^n\mathbb{R} is locally Euclidean of dimension n, hence an n-dimensional manifold.