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Measure Theory 2 | Borel Sigma Algebras [dark version] thumbnail

Measure Theory 2 | Borel Sigma Algebras [dark version]

5 min read

Based on The Bright Side of Mathematics's video on YouTube. If you like this content, support the original creators by watching, liking and subscribing to their content.

TL;DR

Intersecting any collection of sigma algebras on the same set X always yields a sigma algebra.

Briefing

A key takeaway is that the “smallest” sigma algebra containing a chosen collection of sets can be built systematically: take all countable intersections of sigma algebras that already contain the collection. This guarantees the result is again a sigma algebra, and it gives a principled way to define measurable sets without guessing.

Sigma algebras are families of subsets of a set X closed under three operations: they always include the empty set and X, they are closed under complements, and they are closed under countable unions. Starting from many candidate sigma algebras on the same X, intersecting them produces a new sigma algebra—no matter how many are intersected, even if the index set is uncountable. That intersection property becomes a construction tool: if a collection M of subsets of X does not yet form a sigma algebra, one can define σ(M) as the smallest sigma algebra containing M. Concretely, σ(M) is obtained by intersecting all sigma algebras that contain M. This “generated sigma algebra” is often described as the sigma algebra generated by M.

An example with a finite set {a, b, c, d} illustrates how σ(M) is forced to grow. If M consists only of the singletons {a} and {b}, then any sigma algebra containing M must also contain their complements, so {b, c, d} and {a, c, d} must appear. Closure under countable unions (which, in a finite setting, reduces to closure under finite unions) forces the union {a} ∪ {b} = {a, b} to be included. At that point, complements again force {c, d} to be included. Checking the sigma algebra axioms confirms the resulting collection is stable under complements and unions, and by construction it is the smallest possible sigma algebra containing the original singletons.

For infinite sets, the same idea works but the “generation” process can require infinitely many closure steps, making the resulting sigma algebra harder to describe explicitly. That sets up the most important sigma algebra in many analysis and probability settings: the Borel sigma algebra. When X is a topological space (or a metric space like R or R^N), the open sets are the basic objects of interest. The Borel sigma algebra, denoted B(X), is defined as the sigma algebra generated by all open sets. In practice, this means B(X) is the smallest sigma algebra that contains every open set, so it encodes the topological structure of X.

The Borel sigma algebra is large enough to include the sets typically needed for measurement, yet it is not as large as the full power set. That distinction matters because later, when defining measures, the required rules cannot be satisfied on arbitrary subsets of X. The Borel sigma algebra provides the right balance: it is sufficiently rich for real-world measurable sets while still being compatible with the measure axioms that come next.

Cornell Notes

Sigma algebras are collections of subsets of X closed under complements and countable unions, and they always contain ∅ and X. Given any family of subsets M (not necessarily a sigma algebra), there is a smallest sigma algebra containing M, written σ(M). The construction uses intersections: intersect all sigma algebras that contain M; the result is again a sigma algebra and is minimal by inclusion. In a finite example X = {a, b, c, d} with M = {{a}, {b}}, closure forces complements and unions, producing additional sets like {a, b}, {a, c, d}, {b, c, d}, and {c, d}. For topological or metric spaces, the Borel sigma algebra B(X) is σ(T), where T is the collection of open sets; it captures the topology in a measurable way.

Why does intersecting sigma algebras produce another sigma algebra?

If {A_i} is any collection of sigma algebras on the same set X, then their intersection A = ⋂_i A_i still contains ∅ and X because every A_i contains them. If a set E lies in A, then E lies in every A_i, so its complement E^c also lies in every A_i, hence in A. Similarly, if E_1, E_2, … are in A, they are in every A_i, and each A_i is closed under countable unions, so ⋃_n E_n lies in every A_i and therefore in A. This works regardless of whether the index set is countable or not.

How is σ(M) defined when M is just a family of subsets, not yet a sigma algebra?

σ(M) is defined as the smallest sigma algebra containing M. One way to formalize “smallest” is: take all sigma algebras A on X such that M ⊆ A, then intersect them all. The intersection is a sigma algebra, contains M, and is minimal with respect to inclusion because any sigma algebra containing M must contain that intersection.

In the finite example X = {a, b, c, d} with M = {{a}, {b}}, what sets must appear in σ(M)?

Because σ(M) must contain {a} and {b}, it must also contain their complements: {a}^c = {b, c, d} and {b}^c = {a, c, d}. Closure under unions then forces {a} ∪ {b} = {a, b} to be included. Finally, complements of {a, b} force {a, b}^c = {c, d} to be included. The resulting collection is stable under complements and unions, so it is indeed a sigma algebra and is minimal by construction.

What is the Borel sigma algebra B(X), and how does it relate to topology?

If X is a topological space with topology T (the collection of open sets), then B(X) is the sigma algebra generated by T. Symbolically, B(X) = σ(T). This means B(X) is the smallest sigma algebra that contains every open set, so it encodes the topological structure of X in a form suitable for measurement.

Why isn’t the power set always the right choice for measurable sets?

The power set is the largest possible sigma algebra, but later measure definitions require specific consistency rules (the measure axioms). Those rules generally cannot be made to work on arbitrary subsets of X. The Borel sigma algebra is large enough to include the sets needed in analysis and probability, while still being compatible with the measure framework.

Review Questions

  1. Given a family M of subsets of X, how does the intersection-based definition guarantee σ(M) is the smallest sigma algebra containing M?
  2. For X = {a, b, c, d} and M = {{a}, {b}}, list all sets in σ(M) and verify closure under complements and unions.
  3. What is the relationship between a topology T on X and the Borel sigma algebra B(X)?

Key Points

  1. 1

    Intersecting any collection of sigma algebras on the same set X always yields a sigma algebra.

  2. 2

    For any family of subsets M ⊆ P(X), σ(M) is defined as the smallest sigma algebra containing M by intersecting all sigma algebras that contain M.

  3. 3

    In finite settings, generating σ(M) from a small family can be completed by repeatedly applying complements and (countable) unions, which reduce to finite unions.

  4. 4

    In a topological or metric space, the Borel sigma algebra B(X) is the sigma algebra generated by all open sets.

  5. 5

    The Borel sigma algebra is typically large enough for measurement tasks but still smaller than the full power set, which is too large for measure axioms to work cleanly.

Highlights

σ(M) is obtained by intersecting all sigma algebras that contain M, guaranteeing both existence and minimality.
A finite example with X = {a, b, c, d} shows how complements and unions force additional sets beyond the initial singletons.
The Borel sigma algebra B(X) is exactly the sigma algebra generated by open sets, tying measurability to topology.
Borel sigma algebras are rich enough for later measure construction, unlike the full power set.

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