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Ordinary Differential Equations 2 | Definitions thumbnail

Ordinary Differential Equations 2 | Definitions

5 min read

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TL;DR

An ODE of order K includes derivatives up to the K-th derivative, with the highest derivative present defining the order.

Briefing

Ordinary differential equations (ODEs) are defined by how a function’s derivatives relate to the function itself—often through a rule that sets a combination of derivatives equal to zero. In this framework, an ODE of order K is any relation involving derivatives of a function up to the K-th derivative, with the highest derivative present determining the order. The unknown is a function X(t) defined on an interval I, and the equation uses a continuous function F that takes the independent variable t, the function value X(t), and the derivatives X′(t), X″(t), …, X^(K)(t) as inputs. A typical form is F(t, X(t), X′(t), …, X^(K)(t)) = 0, which makes the “order” a direct read-off from the highest derivative appearing.

A second key step is narrowing to the most common practical form: explicit first-order ODEs. “Explicit” means the derivative of interest appears alone on one side of the equation, while everything else sits on the other side. For a first-order explicit ODE, the structure is ẋ = W(t, x), where W is a continuous function defined on a product of intervals (t in I and x in J). This setup becomes even more powerful when multiple variables interact, because coupled equations can be packaged as a system. For example, two first-order equations for variables x1 and x2 can be combined into a vector equation Ẋ = W(t, X), where X(t) = (x1(t), x2(t)) and W maps into R^n. In the system form, the “state” is the vector of unknowns, and the rule W tells how that state changes with time t.

The definitions then pivot to what it means to actually solve an ODE. A solution is a differentiable function α(t) defined on some sub-interval (t0, t1) of the original time interval I. For a system, α(t) must land in the domain U (often an open set in R^n) so that W(t, α(t)) is well-defined. The solution condition is pointwise: for every t in the interval, the derivative α′(t) must equal W(t, α(t)). This is the operational test—plug the candidate function into the equation and verify it holds for all t in the solution’s domain.

To make the definition concrete, the course uses a simple two-dimensional system: x1̇ = x2 and x2̇ = −x1. Here W(t, X) = (x2, −x1), which does not explicitly depend on t. A specific solution is α(t) = (sin t, cos t), since differentiating gives α′(t) = (cos t, −sin t), matching W(t, α(t)). Geometrically, the solution’s image in the plane traces a circle of radius 1, called the orbit of the solution. Scaling the solution by 1/2 produces another valid solution, with an orbit that is a circle of radius 1/2. The takeaway is immediate: systems of ODEs can admit many different solutions, raising the next natural questions—whether solutions exist through prescribed points and whether such solutions are unique.

Cornell Notes

ODEs are defined by relationships among an unknown function and its derivatives. An ODE of order K involves derivatives up to the K-th derivative, with the highest derivative present determining the order. The common “explicit” first-order form isolates the derivative: ẋ = W(t, x). Coupled equations for multiple unknowns combine into a system written as a vector equation Ẋ = W(t, X), where X(t) lies in a domain U in R^n. A solution is a differentiable function α(t) on some interval (t0, t1) such that α′(t) = W(t, α(t)) holds for every t in that interval. The example x1̇ = x2, x2̇ = −x1 yields circular orbits, illustrating how many solutions can exist.

What makes an ODE “order K,” and how is that reflected in its formula?

The order is determined by the highest derivative that appears in the defining relation. If the equation involves derivatives up to X^(K)(t) (and includes the K-th derivative), then it is an ODE of order K. In the general form, a continuous function F takes inputs (t, X(t), X′(t), …, X^(K)(t)) and the equation is set to zero: F(t, X(t), X′(t), …, X^(K)(t)) = 0.

What does “explicit” mean for a first-order ODE?

“Explicit” means the derivative of interest is isolated on one side of the equation. For a first-order explicit ODE, the structure is ẋ = W(t, x), where W contains all the other terms (the function value x and the independent variable t). This contrasts with implicit forms where ẋ might appear mixed with other terms on both sides.

How do two first-order ODEs become a system in vector form?

If x1̇ depends on x1 and x2, and x2̇ depends on x1 and x2, the pair can be packaged as a vector X(t) = (x1(t), x2(t)). The system then becomes Ẋ = W(t, X), where W maps into R^n (here n = 2). This is not treated as two separate independent ODEs; the variables are coupled through the shared function W.

What exactly must a function α(t) satisfy to be a solution of a system of ODEs?

A solution α(t) must be differentiable and must satisfy the equation pointwise on its interval of definition. Concretely, for every t in (t0, t1), the derivative α′(t) must equal W(t, α(t)). Also, α(t) must lie in the domain U so that W(t, α(t)) is well-defined.

Why does the example system produce circular orbits?

For x1̇ = x2 and x2̇ = −x1, the solution α(t) = (sin t, cos t) satisfies α′(t) = (cos t, −sin t) = (x2, −x1) = W(t, α(t)). Since sin^2 t + cos^2 t = 1, the point (x1(t), x2(t)) stays on the circle of radius 1 in the x1–x2 plane. Scaling the solution by 1/2 gives ( (1/2)sin t, (1/2)cos t ), which stays on a circle of radius 1/2 and still satisfies the system.

Review Questions

  1. In an ODE involving derivatives up to X^(3)(t), what is the order and why?
  2. Write the explicit first-order ODE form and the corresponding system vector form, and state how a solution is verified.
  3. For the system x1̇ = x2, x2̇ = −x1, what orbit does α(t) = (sin t, cos t) trace, and how does scaling change it?

Key Points

  1. 1

    An ODE of order K includes derivatives up to the K-th derivative, with the highest derivative present defining the order.

  2. 2

    The general ODE form uses a continuous function F(t, X(t), X′(t), …, X^(K)(t)) set equal to zero.

  3. 3

    “Explicit” first-order ODEs isolate the derivative: ẋ = W(t, x).

  4. 4

    Coupled first-order equations for multiple unknowns combine into a vector system Ẋ = W(t, X) with X(t) in R^n.

  5. 5

    A solution must be differentiable and satisfy α′(t) = W(t, α(t)) for every t in its interval of definition.

  6. 6

    For the system x1̇ = x2 and x2̇ = −x1, solutions trace circles (orbits) in the x1–x2 plane, and scaling yields different valid orbits.

  7. 7

    The existence of multiple solutions motivates the next questions about reaching prescribed points and uniqueness.

Highlights

An ODE’s order is read directly from the highest derivative that appears in the defining equation.
Explicit first-order ODEs take the form ẋ = W(t, x), making the derivative the subject of the equation.
Systems of ODEs are written as vector equations Ẋ = W(t, X), turning coupled dynamics into a single rule.
For x1̇ = x2 and x2̇ = −x1, α(t) = (sin t, cos t) is a solution whose orbit is the unit circle.
Scaling a solution by 1/2 produces another valid solution with a smaller circular orbit, showing solutions are not unique by default.

Topics

Mentioned

  • ODE
  • OD