Get AI summaries of any video or article — Sign up free
Real Analysis 12 | Examples for Limit Superior and Limit Inferior [dark version] thumbnail

Real Analysis 12 | Examples for Limit Superior and Limit Inferior [dark version]

5 min read

Based on The Bright Side of Mathematics's video on YouTube. If you like this content, support the original creators by watching, liking and subscribing to their content.

TL;DR

For any real sequence, lim sup and lim inf always exist as extended-real values (real numbers or ±∞).

Briefing

Limit superior (lim sup) and limit inferior (lim inf) always exist for any real sequence, taking values in the extended real line (real numbers or ±∞). A key takeaway from the opening example is that these two quantities can land anywhere in that extended range: for the sequence a_n = (-1)^n n (−1, 2, −3, 4, −5, …), the even-index subsequence diverges to +∞ while the odd-index subsequence diverges to −∞. That forces lim sup a_n = +∞ and lim inf a_n = −∞, showing that the set of possible values for lim sup and lim inf includes both infinities.

For convergent sequences, lim sup and lim inf collapse to the same real number. If a sequence converges to L, then both lim sup and lim inf equal L because there is only one accumulation value. Conversely, if lim sup and lim inf are equal and finite, there is only one accumulation value, so the sequence must converge to that common value. The same “equality criterion” extends to divergence toward infinity: if the sequence diverges to +∞, then lim sup and lim inf both equal +∞ (and they match as extended-real values, not as finite numbers). Similarly, divergence toward −∞ corresponds to lim sup = lim inf = −∞. Another structural fact used repeatedly in calculations is monotonic ordering: lim sup is always the largest accumulation value, so lim sup ≥ lim inf. In particular, if lim inf = +∞ then lim sup must also be +∞; and if lim sup = −∞, then lim inf must be −∞.

The most practical part comes next: inequalities that relate lim sup/lim inf of sums and products to those of the individual sequences. For two sequences a_n and b_n, one generally has lim sup (a_n + b_n) ≤ lim sup a_n + lim sup b_n, with a crucial caveat about undefined expressions like +∞ + (−∞). The inequality can fail to be meaningful when the right-hand side involves such indeterminate forms, but when the extended-real arithmetic is well-defined, the inequality holds. For products, a similar inequality holds under non-negativity assumptions: lim sup (a_n b_n) ≤ (lim sup a_n)(lim sup b_n), because sign changes can reverse inequalities; again, expressions like 0·(+∞) are treated as undefined and must be handled carefully.

The same style of inequalities applies to lim inf, but with reversed inequality directions. The transcript emphasizes that these are not just abstract rules: concrete examples demonstrate both the direction and when inequalities become strict. For instance, with a_n = 1, −1, 1, −1, … and b_n = 0, 2, 0, 2, …, the sum is constantly 1, so lim sup and lim inf of the sum are 1, while lim sup a_n + lim sup b_n = (1) + (2) = 3 and lim inf a_n + lim inf b_n = (−1) + (0) = −1, giving strict inequalities. A second example modifies a_n to keep it non-negative for the product case, producing a constant product sequence and again showing the inequality can be strict.

Overall, the session’s goal is to equip learners with a small set of reliable extended-real inequalities for lim sup and lim inf—plus the exceptions needed when ±∞ arithmetic becomes indeterminate—so these bounds can be used confidently in later limit computations.

Cornell Notes

Every real sequence has a limit superior and limit inferior, possibly equal to real numbers or to ±∞. For convergence, lim sup and lim inf coincide at the limit value; for divergence to +∞ (or −∞), both lim sup and lim inf equal the corresponding infinity. Always, lim sup is at least lim inf because it represents the largest accumulation value. For sums, lim sup(a_n + b_n) is bounded above by lim sup a_n + lim sup b_n, provided the right-hand side avoids undefined forms like +∞ + (−∞). For products, a comparable bound holds when the sequences are non-negative, and lim inf versions follow with reversed inequality directions.

How does the example a_n = (−1)^n n determine lim sup and lim inf?

The even terms are positive and grow without bound: a_{2k} = 2k → +∞, so +∞ is an accumulation value. The odd terms are negative and decrease without bound: a_{2k+1} = −(2k+1) → −∞, so −∞ is also an accumulation value. Since lim sup is the largest accumulation value, lim sup a_n = +∞. Since lim inf is the smallest accumulation value, lim inf a_n = −∞. The sequence itself does not converge because it keeps oscillating between arbitrarily large positive and negative values.

What exact condition characterizes convergence using lim sup and lim inf?

A sequence converges if and only if lim sup and lim inf are equal and finite. If the sequence converges to L, then there is only one accumulation value, so both lim sup and lim inf equal L. Conversely, if lim sup a_n = lim inf a_n = L for some real L, then there cannot be two different accumulation values; that forces the sequence to converge to L.

What changes when the limit is +∞ or −∞?

When the sequence diverges to +∞, both lim sup and lim inf equal +∞ (they match as extended-real values). When the sequence diverges to −∞, both lim sup and lim inf equal −∞. The transcript stresses that these are not “real numbers,” so the equality is in the extended-real sense: lim sup = lim inf = +∞ (or −∞), not a finite equality.

Why does the inequality for lim sup of sums require care with infinities?

The general bound is lim sup(a_n + b_n) ≤ lim sup a_n + lim sup b_n. But the right-hand side might be undefined if it becomes an indeterminate form like +∞ + (−∞). In such cases, the inequality is not meaningful because extended-real addition is not defined for that combination. When the arithmetic is well-defined (e.g., +∞ + 5 = +∞), the inequality can be applied safely.

Why is the product inequality restricted to non-negative sequences?

For products, the inequality lim sup(a_n b_n) ≤ (lim sup a_n)(lim sup b_n) is stated for non-negative sequences. If signs vary, multiplying can flip inequality behavior, breaking the simple upper-bound relationship. The transcript also flags undefined cases like 0·(+∞), which must be avoided when working with extended-real products.

How do the lim inf inequalities relate to the lim sup inequalities?

The lim inf inequalities mirror the lim sup ones but with the inequality direction reversed. So where lim sup(a_n + b_n) is bounded above, lim inf(a_n + b_n) is bounded below in the corresponding way. The same reversal applies to the product inequalities, again under the appropriate non-negativity and “defined arithmetic” conditions.

Review Questions

  1. If lim sup a_n = 3 and lim inf a_n = 3, what can be concluded about the sequence a_n?
  2. Give an example of how lim sup(a_n + b_n) can be strictly less than lim sup a_n + lim sup b_n.
  3. Under what conditions is it valid to use an inequality of the form lim sup(a_n b_n) ≤ (lim sup a_n)(lim sup b_n)?

Key Points

  1. 1

    For any real sequence, lim sup and lim inf always exist as extended-real values (real numbers or ±∞).

  2. 2

    A sequence converges iff lim sup and lim inf are equal and finite, and the common value is the limit.

  3. 3

    If a sequence diverges to +∞ (or −∞), then lim sup and lim inf both equal the corresponding infinity.

  4. 4

    lim sup is always at least lim inf because it represents the largest accumulation value.

  5. 5

    For sums, lim sup(a_n + b_n) ≤ lim sup a_n + lim sup b_n, but the right-hand side must avoid undefined forms like +∞ + (−∞).

  6. 6

    For products, a comparable lim sup inequality holds for non-negative sequences, with special attention to undefined products like 0·(+∞).

  7. 7

    The lim inf inequalities follow the same structure as lim sup inequalities but with reversed inequality directions.

Highlights

The alternating-growth sequence a_n = (−1)^n n forces lim sup a_n = +∞ and lim inf a_n = −∞ via its even and odd subsequences.
Convergence is equivalent to lim sup and lim inf matching as finite real numbers—there is then only one accumulation value.
Extended-real arithmetic matters: inequalities involving lim sup of sums/products require the expressions on the right to be well-defined (no +∞ + (−∞), no 0·(+∞)).
For sums and products, lim sup provides an upper bound (under conditions), while lim inf provides the corresponding lower bound with reversed inequality direction.

Topics