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Real Analysis 45 | Taylor's Theorem [dark version] thumbnail

Real Analysis 45 | Taylor's Theorem [dark version]

4 min read

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TL;DR

Taylor’s theorem approximates f(x) near an expansion point x0 using derivatives at x0 plus a remainder term.

Briefing

Taylor’s theorem turns local smoothness into a controlled approximation: if a function has enough derivatives, its value near a chosen expansion point can be written as a polynomial whose coefficients come from derivatives at that point, plus a remainder term that shrinks predictably as the input gets close. That remainder behavior is what makes the approximation more than a heuristic—linearization and higher-order polynomial approximations come with a quantitative error structure.

The setup starts by fixing an expansion point x0 and looking at nearby inputs x. Writing x as x0 + H (with H small) makes the formulas cleaner. The simplest case is the derivative definition: the best linear approximation takes the form f(x0 + H) = f(x0) + f'(x0)H + R(H)·H, where the remainder factor satisfies R(H) → 0 as H → 0. In other words, the tangent line captures the function up to first order, and the leftover term becomes negligible compared to H.

Taylor’s theorem generalizes this idea to higher degrees. With enough derivatives, the function admits an nth-order Taylor polynomial:

f(x0 + H) = Σ_{k=0}^{n} [f^{(k)}(x0)/k!] · H^k + R_n(H).

The polynomial part has degree at most n because the powers of H run from H^0 up to H^n. The coefficients are determined by the derivatives of f at x0, scaled by factorials (so the quadratic term becomes (1/2!)f''(x0)H^2, the cubic term (1/3!)f'''(x0)H^3, and so on). The remainder term R_n(H) accounts for what the polynomial misses.

Crucially, the remainder can be expressed using an (n+1)st derivative evaluated at an intermediate point C. For H such that x0 + H stays inside the interval I, there exists C between x0 and x0 + H with

R_n(H) = [f^{(n+1)}(C)/(n+1)!] · H^{n+1}.

This “between points” condition matters: even though C is not known explicitly, its location guarantees the estimate needed for error bounds. The theorem also admits a compact big-O form when the exact constant is not the focus: writing f(x0 + H) = (Taylor polynomial) + O(H^{n+1}) signals that the neglected part scales like H^{n+1} as H → 0.

Finally, the same statement can be rewritten in terms of x directly instead of H, using x − x0 in place of H. Either way, the takeaway is consistent: Taylor polynomials provide increasingly accurate local approximations, and the remainder’s order—n+1—tells exactly how fast the error shrinks as the input approaches the expansion point. That structure underpins a wide range of applications, from numerical methods to analysis of function behavior.

Cornell Notes

Taylor’s theorem gives a local approximation of a sufficiently differentiable function near an expansion point x0. For x = x0 + H (with x0 + H inside the interval I), f(x0 + H) equals the nth-order Taylor polynomial—built from derivatives f^{(k)}(x0) divided by k!—plus a remainder term R_n(H). The remainder has a precise form: there exists a point C between x0 and x0 + H such that R_n(H) = [f^{(n+1)}(C)/(n+1)!]·H^{n+1}. This implies the error shrinks on the order of H^{n+1}, often summarized as O(H^{n+1}). The theorem also has an equivalent version written using powers of (x − x0) instead of H.

How does the “best linear approximation” emerge from the definition of the derivative?

Using H so that x = x0 + H, the derivative definition yields f(x0 + H) = f(x0) + f'(x0)H + R(H)·H. The key property is that R(H) → 0 as H → 0, meaning the leftover term becomes negligible compared with H. That is exactly why the tangent line is the best first-order (linear) approximation near x0.

What is the general form of the nth-order Taylor polynomial around x0?

For f that is (n+1)-times differentiable on an interval I, and for H such that x0 + H ∈ I, the polynomial part is Σ_{k=0}^{n} [f^{(k)}(x0)/k!]·H^k. The coefficients come from derivatives at x0, and factorials appear in the denominators. The degree is at most n because the highest power of H is H^n.

Why does the remainder term involve an (n+1)st derivative evaluated at an intermediate point C?

Taylor’s theorem guarantees that there exists C between x0 and x0 + H such that the remainder is R_n(H) = [f^{(n+1)}(C)/(n+1)!]·H^{n+1}. This structure ties the error to how the function behaves at order n+1, not just at x0. Even without knowing C exactly, its location ensures the remainder has the correct magnitude.

What does the big-O notation O(H^{n+1}) mean in this context?

When the exact remainder constant is not needed, the theorem can be summarized as f(x0 + H) = (Taylor polynomial) + O(H^{n+1}). This indicates the remainder term scales like H^{n+1} as H → 0—so the error decreases at least as fast as the (n+1)st power of the step size.

How can the theorem be written using x instead of H?

Since H = x − x0, the same Taylor polynomial and remainder can be expressed in terms of (x − x0). The coefficients still depend on derivatives at x0, and the remainder still has order (x − x0)^{n+1}, with an intermediate point between x0 and x.

Review Questions

  1. What conditions on f and on the point x (relative to x0) are required for Taylor’s theorem to apply?
  2. Write the formula for the nth-order Taylor polynomial and identify where the factorials appear.
  3. How does the remainder term’s dependence on H (or x − x0) determine the accuracy of the approximation?

Key Points

  1. 1

    Taylor’s theorem approximates f(x) near an expansion point x0 using derivatives at x0 plus a remainder term.

  2. 2

    For x = x0 + H, the nth-order Taylor polynomial is Σ_{k=0}^{n} [f^{(k)}(x0)/k!]·H^k.

  3. 3

    The theorem requires f to be (n+1)-times differentiable on an interval I containing x0 and x0 + H.

  4. 4

    The remainder has a precise form: R_n(H) = [f^{(n+1)}(C)/(n+1)!]·H^{n+1} for some C between x0 and x0 + H.

  5. 5

    Because the remainder involves H^{n+1}, the approximation error shrinks on the order of H^{n+1} as H → 0.

  6. 6

    The same result can be expressed using (x − x0) instead of H, with the same derivative-based coefficients.

  7. 7

    Big-O notation O(H^{n+1}) provides a shorthand for the remainder’s order when exact constants are unnecessary.

Highlights

The tangent-line approximation is recovered as the n=1 case, with the remainder factor R(H) → 0 as H → 0.
The nth-order Taylor polynomial uses derivatives at x0 scaled by factorials: f^{(k)}(x0)/k!.
A point C between x0 and x0 + H always exists so the remainder equals [f^{(n+1)}(C)/(n+1)!]·H^{n+1}.
Writing the remainder as O(H^{n+1}) captures the error’s rate of decay without tracking the exact constant.

Topics

  • Taylor's Theorem
  • Taylor Polynomial
  • Remainder Term
  • Big O Notation
  • Local Approximation

Mentioned

  • O