Get AI summaries of any video or article — Sign up free
Resonance || Rules for drawing Resonance Structure || GOC || Lec 02  || Dr Rizwana thumbnail

Resonance || Rules for drawing Resonance Structure || GOC || Lec 02 || Dr Rizwana

Dr Rizwana Mustafa·
4 min read

Based on Dr Rizwana Mustafa's video on YouTube. If you like this content, support the original creators by watching, liking and subscribing to their content.

TL;DR

Resonance structures are not literal molecular geometries; the real molecule corresponds to a resonance hybrid that averages delocalized bonding.

Briefing

Resonance structures aren’t meant to be literal snapshots of a molecule’s actual bonding. Instead, they’re bookkeeping devices that approximate how electrons are delocalized—so only certain drawings qualify as valid resonance contributors. The key practical takeaway: a correct resonance structure must preserve the molecule’s overall bonding “rules” (valency), keep the same electron-counting features, and show changes that come only from electron movement, not from atoms swapping places.

A major point is that resonance structures do not match the real structure bond-for-bond. Benzene is used to illustrate the mismatch: although multiple resonance forms can be drawn for benzene, none of those drawn structures reproduces benzene’s observed bond lengths and angles. The lecture contrasts pure single-bond length (about 1.34 Å) and pure double-bond length (about 1.54 Å) with benzene’s intermediate bond length (about 1.39 Å). That intermediate value signals a resonance hybrid—an averaged, delocalized bonding picture—rather than any single drawn resonance form being the “true” structure.

From there, the lecture lays out rules for drawing resonance structures correctly. First, each resonance contributor must be a “bonafide” Lewis structure: every atom must satisfy its typical valency. If a proposed resonance form violates valency—for example, by placing an impossible charge distribution that implies carbon would need more than its maximum bonding capacity—then that contributor is invalid and contributes essentially zero toward the real resonance hybrid.

Second, resonance must involve only electron shifts. Atoms and their positions cannot move to create a new arrangement; only the placement of electrons changes. An example is given where a double bond shifts, changing where positive charge appears on carbon, but without relocating atoms—this kind of electron-only rearrangement is acceptable, while any structure requiring an atom to “move” is not a proper resonance contributor.

Third, all valid resonance structures must have the same number of unpaired electrons. If one structure implies free radicals (unpaired electrons) while another does not, they cannot all be resonance forms of the same molecule.

Fourth, the lecture emphasizes planarity. For p-orbital overlap to support delocalization, the relevant atoms and π systems must lie in the same plane. Bulky substituents that twist the π system out of planarity prevent effective parallel p-orbital overlap, making resonance drawing invalid for that case.

Taken together, these rules turn resonance from a purely drawing exercise into a consistency check: valency must hold, electron movement must be the only change, unpaired-electron counts must match, and geometry must allow p-orbital overlap. When those conditions fail, the proposed resonance structure is not a meaningful contributor to the resonance hybrid.

Cornell Notes

Resonance structures are valid only when they represent the same molecule’s electron delocalization through electron shifts—not atom rearrangements. Benzene illustrates why: none of its drawn resonance forms reproduces the observed intermediate bond length (about 1.39 Å), so the real structure is a resonance hybrid. A correct resonance contributor must satisfy valency rules (a “bonafide” Lewis structure), keep the same number of unpaired electrons across all contributors, and show changes caused solely by moving electrons (e.g., shifting a π bond and the associated charges). Finally, resonance requires planarity so p-orbital overlap can occur; bulky groups that twist the π system prevent effective overlap and invalidate resonance contributors.

Why doesn’t any single benzene resonance structure match benzene’s real bonding?

Benzene’s observed bond length is intermediate between typical single and double bonds. The lecture cites ~1.34 Å for a pure single bond and ~1.54 Å for a pure double bond, while benzene’s bonds measure ~1.39 Å. That means the bonding is delocalized across the ring. Resonance drawings show possible electron arrangements, but the actual molecule behaves like an averaged resonance hybrid rather than matching any one drawn structure exactly.

What does “bonafide Lewis structure” mean for resonance contributors?

Each resonance form must respect valency: every atom must have the maximum number of bonds it can form (based on typical bonding capacity). If a proposed resonance structure implies impossible bonding—such as carbon needing more than four bonds—then it’s not a valid contributor. The lecture notes that such an invalid form would contribute essentially zero toward the real resonance hybrid.

What kinds of changes are allowed when converting one resonance structure to another?

Only electron movement is allowed. The lecture stresses that atoms (like H, C, O, halogens) cannot shift positions. A valid resonance form can be created by moving π electrons (for example, shifting a double bond so charge distribution changes accordingly), but the skeleton of atoms must remain fixed.

How does the rule about unpaired electrons help identify invalid resonance structures?

All resonance contributors must have the same number of unpaired electrons. If one structure implies free radicals (unpaired electrons) while another implies none, they cannot be resonance forms of the same molecule. The lecture uses an example where one proposed structure shows unpaired electrons/free radical character while another does not, making the set inconsistent.

Why does planarity matter for resonance?

Resonance relies on parallel p-orbital overlap. If bulky substituents twist the π system out of the plane, p-orbitals can’t align for effective overlap, so the delocalization implied by resonance isn’t physically supported. The lecture concludes that resonance structures can be drawn only when the relevant single/double bond system can be placed in a plane.

Review Questions

  1. List the main conditions a resonance structure must satisfy to be a valid contributor to a resonance hybrid.
  2. Explain, using benzene bond lengths, why resonance structures are not literal representations of the molecule’s actual structure.
  3. Give an example of an invalid resonance contributor and justify which rule it violates (valency, electron-only change, unpaired electrons, or planarity).

Key Points

  1. 1

    Resonance structures are not literal molecular geometries; the real molecule corresponds to a resonance hybrid that averages delocalized bonding.

  2. 2

    Benzene demonstrates this mismatch: its bond length (~1.39 Å) is intermediate between typical single (~1.34 Å) and double (~1.54 Å) bonds.

  3. 3

    A valid resonance contributor must be a bonafide Lewis structure with correct valency for every atom; impossible bonding patterns make the contributor effectively zero.

  4. 4

    Only electrons may move between resonance forms; atoms cannot relocate to create a new structure.

  5. 5

    All resonance contributors must have the same number of unpaired electrons; differing radical character invalidates the set.

  6. 6

    Effective resonance requires planarity so p-orbital overlap can occur; twisting from bulky groups prevents the delocalization implied by resonance.

Highlights

Benzene’s observed bond length (~1.39 Å) sits between single (~1.34 Å) and double (~1.54 Å), signaling delocalization rather than any one resonance form being “the” structure.
A resonance contributor must satisfy valency rules; if carbon would need more than four bonds (or oxygen more than two), that structure is invalid.
Resonance is electron-only: shifting π electrons changes charge distribution, but atoms never move.
Resonance requires planarity for p-orbital overlap; bulky substituents that twist the π system block resonance delocalization.

Topics

  • Resonance Structures
  • Lewis Structures
  • Valency Rules
  • Electron Delocalization
  • Planarity and p-Orbital Overlap

Mentioned