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Start Learning Sets 5 | Range, Image and Preimage [dark version] thumbnail

Start Learning Sets 5 | Range, Image and Preimage [dark version]

4 min read

Based on The Bright Side of Mathematics's video on YouTube. If you like this content, support the original creators by watching, liking and subscribing to their content.

TL;DR

A function f: A → B assigns each x ∈ A to a single output f(x) ∈ B.

Briefing

A map’s “range” tells which outputs get hit at all, but the more precise tools are the image of a subset and the pre-image of a subset—definitions that let mathematicians track what happens to selected inputs (or selected outputs) under a function. Starting from the basic setup of a function as a relation that assigns each element of a domain set A to an element of a codomain set B, the discussion first uses a familiar example: sending a natural number x to x². Visualizing arrows from natural numbers to integers makes it clear that not every integer appears as a square, motivating the range as the set of all codomain elements y for which some x in A satisfies f(x)=y.

The range is then generalized in a way that leads naturally to the next step: instead of asking which outputs occur overall, ask which outputs occur from a chosen subset of inputs. For a subset à ⊆ A, the image f(Ã) is defined as the collection of all y in B such that there exists an x in à with f(x)=y. This turns “apply the function” into a set operation: feed in a whole group of inputs, and collect every output they produce. The transcript emphasizes a compact notation often used in textbooks—writing sets like {f(x) | x ∈ Ã}—and warns that parentheses can be confusing when the objects involved are sets rather than single elements.

To show how geometry can guide intuition, the discussion then considers a function on pairs of real numbers: (x1, x2) ↦ x1² + x2². In the plane R×R, points at a fixed distance from the origin form circles, and the formula matches the Pythagorean theorem: x1² + x2² equals the squared radius. That means every point on a circle maps to the same nonnegative number, and varying the radius produces exactly all real values ≥ 0. So the range of this map is the half-line [0, ∞).

The final key concept flips the direction. Given a subset B̃ ⊆ B, the pre-image f⁻¹(B̃) is the set of all x in A that land inside B̃ after applying f—formally, all x such that f(x) ∈ B̃. A crucial clarification follows: the “−1” here does not mean an inverse function; it only signals that the input set is taken from the codomain side.

An explicit number example ties everything together. Define f on natural numbers to integers by mapping even x to 0 and odd x to x itself. The image of {2,3,4} is {0,3} because 2 and 4 are even (both map to 0) while 3 is odd (maps to 3). The pre-image of {0} consists of all even natural numbers, since every even input maps to 0. Together, range, image, and pre-image provide a precise language for tracking how functions move information between sets—either from inputs to outputs, or from outputs back to the inputs that produce them.

Cornell Notes

Functions assign elements from a domain A to elements in a codomain B. The range of f is the set of all y ∈ B that actually occur as outputs, meaning y = f(x) for some x ∈ A. For a subset à ⊆ A, the image f(Ã) collects every output produced by inputs in Ã: f(Ã) = {y ∈ B | ∃x ∈ à with f(x)=y}. For a subset B̃ ⊆ B, the pre-image f⁻¹(B̃) collects all inputs that land in B̃: f⁻¹(B̃) = {x ∈ A | f(x) ∈ B̃}. The “−1” symbol does not imply an inverse function; it only indicates reversing the set-direction for the definition.

How does the definition of range differ from the definition of image of a subset?

Range asks which outputs occur somewhere in the entire domain A: it is {y ∈ B | ∃x ∈ A such that f(x)=y}. Image of a subset à narrows the question to only those outputs produced by inputs inside Ã: f(Ã) = {y ∈ B | ∃x ∈ à with f(x)=y}. So range uses the whole domain, while image uses a chosen subset of inputs.

Why does the map (x1, x2) ↦ x1² + x2² have range equal to all real numbers ≥ 0?

The expression x1² + x2² equals the squared distance from the origin in the plane R×R (via the Pythagorean theorem). Squared radius can never be negative, so outputs are always ≥ 0. Every nonnegative value can be achieved by choosing points at the corresponding distance from the origin, so the range is exactly [0, ∞).

What does f⁻¹(B̃) mean if f has no inverse function?

In this context, f⁻¹(B̃) is the pre-image of a set B̃ ⊆ B, defined as {x ∈ A | f(x) ∈ B̃}. The “−1” is notation for reversing the set-direction (from outputs back to inputs), not for constructing an inverse function f⁻¹: B → A.

Given f on natural numbers where even x maps to 0 and odd x maps to x, what is the image of {2,3,4}?

Compute outputs for each element: f(2)=0 (even), f(3)=3 (odd), f(4)=0 (even). Collect distinct outputs into a set, giving f({2,3,4}) = {0,3}.

For the same function, what is the pre-image of {0}?

The pre-image f⁻¹({0}) is the set of all natural numbers x such that f(x) ∈ {0}. Since f(x)=0 exactly when x is even, the pre-image is the even natural numbers (e.g., {2,4,6,8,...}).

Review Questions

  1. Explain the difference between f(Ã) and f⁻¹(B̃) using set-builder notation.
  2. For the function (x1, x2) ↦ x1² + x2², what geometric objects in R×R map to the same output value?
  3. Why is the symbol f⁻¹(B̃) not the same thing as an inverse function?

Key Points

  1. 1

    A function f: A → B assigns each x ∈ A to a single output f(x) ∈ B.

  2. 2

    The range of f is the set of all y ∈ B for which some x ∈ A satisfies f(x)=y.

  3. 3

    For à ⊆ A, the image f(Ã) is {y ∈ B | ∃x ∈ à with f(x)=y}.

  4. 4

    For B̃ ⊆ B, the pre-image f⁻¹(B̃) is {x ∈ A | f(x) ∈ B̃}.

  5. 5

    The “−1” in f⁻¹(B̃) denotes pre-image notation, not an inverse function.

  6. 6

    In the example (x1, x2) ↦ x1² + x2², the range is exactly all real numbers ≥ 0 because outputs equal squared radius.

  7. 7

    In the parity-based example, the image of {2,3,4} is {0,3} and the pre-image of {0} is the set of even natural numbers.

Highlights

Range tracks which codomain elements are actually hit: y appears in the range iff y=f(x) for some x in the domain.
Image and pre-image turn function application into set-to-set operations: f(Ã) collects outputs from a subset Ã, while f⁻¹(B̃) collects inputs that land in B̃.
The map (x1, x2) ↦ x1² + x2² produces exactly the nonnegative reals because it equals squared distance from the origin.
The notation f⁻¹(B̃) does not require an inverse function; it only reverses the set-direction in the definition.
For the even/odd function on natural numbers, even inputs collapse to 0, making the pre-image of {0} precisely the even naturals.

Topics

  • Functions and Maps
  • Range
  • Image of a Subset
  • Pre-image of a Subset
  • Set-Builder Notation