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Unbounded Operators 1 | Introduction and Definitions [dark version] thumbnail

Unbounded Operators 1 | Introduction and Definitions [dark version]

5 min read

Based on The Bright Side of Mathematics's video on YouTube. If you like this content, support the original creators by watching, liking and subscribing to their content.

TL;DR

Unbounded operators arise naturally in partial differential equations and are required for quantum mechanics because key operator relations (e.g., involving position and momentum) cannot be achieved with bounded operators alone.

Briefing

Unbounded operators are essential in functional analysis because they naturally arise in both partial differential equations and quantum mechanics—settings where the usual “bounded operator” framework breaks down. In quantum mechanics, the position and momentum observables are represented by operators X and P, and the non-commutativity of measurements shows up as a specific operator relation: the compositions XP and PX differ by a term proportional to the identity (with an imaginary unit involved). That kind of relation cannot be satisfied if one restricts attention to bounded operators alone, forcing a broader definition of linear operators.

The course then sets up the mathematical groundwork needed to talk about operators that may be unbounded. Start with two normed vector spaces, X and Y, over a common field F (either real numbers or complex numbers, with complex spaces suggested as the default in most applications). Unlike bounded operators, an unbounded operator is not required to act on the entire space X. Instead, it is defined only on a subspace D ⊆ X, called the domain. A linear operator T maps each x in D to an element T x in Y.

Because different texts use different shorthand, the transcript emphasizes notation: some authors write T ⊆ or omit the explicit domain in the symbol, while others treat an operator as the pair of its action together with its restriction to D. For this course, the key new concept is “densely defined” operators. An operator T is densely defined when its domain D is dense in X, meaning the closure of D equals all of X. This matters only in infinite-dimensional spaces: in finite dimensions, any proper subspace cannot be dense, so the phenomenon of having a smaller but dense domain is essentially an infinite-dimensional feature.

With the domain in place, standard operator substructures must be defined with care. The range (or image) of T consists of all outputs T x with x drawn from D, producing a subspace of Y. The kernel consists of all x in D such that T x = 0, forming a subspace of X. These definitions mirror the bounded case but explicitly respect the restricted domain.

The transcript then recalls boundedness. A linear operator T is bounded if there exists a finite constant C such that for every x in D, the norm of T x in Y is at most C times the norm of x in X. Equivalently, the operator norm stays finite. If no such finite C exists—so the operator norm effectively becomes infinite—then T is called unbounded. A crucial equivalence from functional analysis ties boundedness to continuity: a linear map is bounded if and only if it is continuous at all points of its domain. Therefore, unbounded operators must be discontinuous everywhere on their domain. The course flags this as another reason unbounded operators are inherently tied to infinite-dimensional settings, where continuity can fail in ways impossible in finite dimensions.

Overall, the definitions build a bridge from physical and PDE motivations to a precise functional-analytic framework: linear operators with restricted, often dense domains, whose failure of boundedness corresponds to pervasive discontinuity—exactly the behavior needed to model quantum observables and differential operators.

Cornell Notes

Unbounded operators become unavoidable when modeling quantum mechanics and partial differential equations, because key operator relations (like those involving position and momentum) cannot be realized within the bounded-operator framework. Mathematically, an operator T is defined as a linear map from a dense subspace D of a normed space X into another normed space Y, rather than acting on all of X. Boundedness means there is a finite constant C with ||T x|| ≤ C||x|| for all x in D; bounded linear maps are equivalent to continuous maps on their domains. When no such finite C exists, the operator is unbounded, which forces discontinuity at every point of its domain. These phenomena are essentially infinite-dimensional, since only then can a proper subspace be dense in the whole space.

Why do position and momentum operators force the need for unbounded operators?

Quantum mechanics requires operators X (position) and P (momentum) whose measurement order matters, meaning XP ≠ PX. The difference between these compositions is proportional to the identity operator (including an imaginary unit factor). The transcript emphasizes that such an operator relation cannot be satisfied using only bounded operators, so the theory must extend linear operators beyond the bounded case—leading to unbounded operators.

What changes in the definition of an operator when unbounded operators are allowed?

An unbounded operator T is still linear, but it need not act on the entire space X. Instead, it is defined on a subspace D ⊆ X called the domain, mapping each x ∈ D to T x ∈ Y. This domain restriction is central: range and kernel must be computed using only x from D.

What does “densely defined” mean, and why is it important?

T is densely defined if its domain D is dense in X, meaning the closure of D (in X) equals all of X. The transcript notes this is only interesting in infinite-dimensional spaces: in finite dimensions, a proper subspace cannot be dense, so densely defined operators would effectively have to be defined on all of X.

How are range and kernel defined for operators with restricted domains?

The range of T is {T x : x ∈ D}, a subspace of Y. The kernel is {x ∈ D : T x = 0}, a subspace of X. Both definitions explicitly depend on the domain D, unlike the bounded-operator setting where the domain is often the whole space.

What is the precise criterion for boundedness, and how does it connect to continuity?

T is bounded if there exists a finite constant C > 0 such that for every x ∈ D, ||T x||_Y ≤ C||x||_X. This corresponds to having a finite operator norm. The transcript recalls an equivalence: a linear map is bounded if and only if it is continuous at all points in its domain. Consequently, an unbounded operator must be discontinuous everywhere on its domain.

Why can unbounded operators not occur in finite-dimensional spaces?

The transcript ties unboundedness to failure of continuity. In finite dimensions, every linear map is automatically continuous, so boundedness always holds. Since unbounded operators must be discontinuous at all points of their domain, they cannot exist in the finite-dimensional setting described.

Review Questions

  1. How does restricting an operator to a dense domain D change the definitions of range and kernel?
  2. State the boundedness condition using a constant C and norms, and explain its equivalence to continuity for linear maps.
  3. Why does the transcript claim unbounded operators are inherently linked to infinite-dimensional spaces?

Key Points

  1. 1

    Unbounded operators arise naturally in partial differential equations and are required for quantum mechanics because key operator relations (e.g., involving position and momentum) cannot be achieved with bounded operators alone.

  2. 2

    An unbounded operator T is a linear map defined on a subspace D ⊆ X (its domain), not necessarily on all of X, and it maps into another normed space Y.

  3. 3

    A densely defined operator has a domain D whose closure equals X, a property that is meaningful primarily in infinite-dimensional spaces.

  4. 4

    Range and kernel must be computed using only elements from the domain D: range is {T x : x ∈ D} and kernel is {x ∈ D : T x = 0}.

  5. 5

    Boundedness means there exists a finite constant C such that ||T x|| ≤ C||x|| for all x in D; unboundedness corresponds to the absence of such a finite bound.

  6. 6

    For linear operators, boundedness is equivalent to continuity on the domain, so unbounded operators must be discontinuous at every point of their domain.

  7. 7

    Because every linear map is continuous in finite dimensions, unbounded operators cannot occur in finite-dimensional normed spaces.

Highlights

Quantum mechanics demands operators for position and momentum whose non-commutativity cannot be realized with bounded operators, forcing the unbounded-operator framework.
Unbounded operators are defined on a domain D ⊆ X, and “densely defined” means the closure of D equals X.
Bounded linear operators are exactly the continuous ones; unbounded operators must be discontinuous everywhere on their domain.
In finite dimensions, linear maps are always continuous, so unbounded operators are an inherently infinite-dimensional phenomenon.

Topics

  • Unbounded Operators
  • Functional Analysis
  • Operator Domains
  • Densely Defined Operators
  • Boundedness and Continuity