What if the Earth were Hollow?
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At the equator, Earth’s rotation creates a Coriolis-driven eastward mismatch that can make a falling object hit the tunnel wall after only a few kilometers.
Briefing
Digging a tunnel straight through Earth and dropping into it would turn gravity into a near clockwork ride: ignoring air resistance and rotation effects, the trip from one side to the other would take about 37 minutes, with the traveler accelerating for the first half, reaching a weightless midpoint, then slowing symmetrically on the way out. The key complication is Earth’s rotation. At the equator, the ground is moving eastward at roughly 1,670 km/h; deeper down, the material beneath still completes a rotation once per day but covers less distance, so it moves more slowly. A falling object would therefore move east faster than the surrounding rock after only a few kilometers, colliding with the tunnel wall—an effect demonstrated in spirit by miners who dropped cannon balls down a mile-long shaft near Lake Superior and found they never reached the bottom.
If the tunnel instead runs pole-to-pole, the Coriolis effect largely disappears, letting gravity dominate. For the first ~3,000 km—about halfway to the center—gravity stays close to constant because most of Earth’s mass lies below the traveler in a way that keeps the net pull similar to what’s felt at the surface. That near-constant acceleration would build speed rapidly: the traveler would be falling about 8 km every second, and the halfway point would arrive in roughly 13 minutes. Near the outer core, gravity becomes strongest, but only slightly stronger than surface gravity; as the traveler moves closer to the center, mass above begins to cancel mass below, weakening the net force.
At the exact center, gravitational pull cancels in every direction. The traveler would feel weightless—no preferred “up” or “down”—while still moving extremely fast, around 22,000 miles per hour (about 6 miles per second). After passing the center, the motion reverses: the traveler is pulled weakly at first, then more strongly, until coming to rest at the opposite side. The total time comes out to about 37 minutes.
The transcript then pivots to a different “hollow Earth” thought experiment. Earth’s real interior is hot and molten near the middle, and the deepest human drilling—the Kola Superdeep borehole in Russia—reached only 12 km before hitting extreme temperatures around 180°C. If Earth were hollow but kept the same total mass, concentrating that mass in a thin shell would remove the magnetic field, since Earth’s magnetic field is tied to the molten iron core. Without that shielding, solar wind and storms would deliver radiation more directly, making auroras visible everywhere. Inside the hollow cavity, gravity from the spherical shell would cancel perfectly, leaving occupants floating freely—though they’d need a space suit because there wouldn’t be enough air to fill the entire interior. Finally, the discussion notes that outside such a hollow Earth, gravity and orbital behavior would look essentially unchanged: falling objects would still accelerate at about 9.8 m/s², trajectories like a baseball’s would match, and the Moon’s orbit would remain the same.
Cornell Notes
A straight tunnel through Earth would be a fast, weightless ride if rotation and friction are ignored. With a pole-to-pole tunnel, gravity is roughly constant for the first ~3,000 km, letting a traveler reach the center in about 13 minutes while accelerating to extreme speeds. Near the center, mass above cancels mass below, producing weightlessness; the traveler would still be moving at about 22,000 miles per hour. After passing the center, gravity strengthens again in reverse, bringing the traveler to rest on the opposite side in about 37 minutes total. The hollow-Earth twist keeps the same mass but concentrates it in a thin shell, removing Earth’s magnetic field and changing radiation/aurora conditions while leaving outside gravity and orbits essentially the same.
Why would a vertical tunnel at the equator cause a falling object to hit the wall quickly?
What changes when the tunnel runs pole-to-pole instead of equator-to-equator?
How does gravity behave during the first half of the trip toward Earth’s center?
What happens at the center of a tunnel-through-Earth drop?
If Earth were hollow but had the same total mass, what would change and what would stay the same?
Review Questions
- In a tunnel-through-Earth scenario, how do rotation and the Coriolis effect alter the outcome compared with a pole-to-pole tunnel?
- Why does net gravity weaken as you approach Earth’s center, and what does that imply for weightlessness?
- What two major consequences follow from concentrating Earth’s mass into a thin shell in a hollow-Earth model?
Key Points
- 1
At the equator, Earth’s rotation creates a Coriolis-driven eastward mismatch that can make a falling object hit the tunnel wall after only a few kilometers.
- 2
A pole-to-pole tunnel avoids most Coriolis complications, allowing gravity to produce a symmetric trip through Earth.
- 3
Ignoring air resistance and friction, gravity is roughly constant for the first ~3,000 km, enabling rapid acceleration toward the center.
- 4
Net gravitational force cancels at the center, creating weightlessness even while the traveler moves at about 22,000 miles per hour.
- 5
After passing the center, gravity reverses its effect, bringing the traveler to rest on the opposite side in about 37 minutes total.
- 6
Real drilling is limited by extreme heat: the Kola Superdeep borehole reached 12 km before temperatures around 180°C forced a stop.
- 7
A hollow-Earth mass shell would remove Earth’s magnetic field (changing aurora and radiation exposure) while leaving outside gravity and orbital motion largely unchanged.