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Ordinary Differential Equations 16 | Periodic Solutions and Fixed Points [dark version] thumbnail

Ordinary Differential Equations 16 | Periodic Solutions and Fixed Points [dark version]

5 min read

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TL;DR

Fixed points are exactly the states where the vector field vanishes (V(x*) = 0), producing constant solutions α(t) = x* for all t.

Briefing

A system of ordinary differential equations can produce three qualitatively different long-term behaviors—trajectories that never repeat, trajectories that loop periodically, and trajectories that stay put forever—and those behaviors can be read directly from the phase portrait. Fixed points occur exactly where the vector field vanishes: if V(x*) = 0, then the constant solution α(t) = x* satisfies α(t) = α(0) for all t, so the orbit is just a single point. Periodic solutions occur when the state repeats after some time T: α(t + T) = α(t) for every t, which forces the orbit to be a closed curve. In contrast, injective (non-repeating) solutions trace out orbits that do not hit the same point twice; among these, only the injective case may fail to exist for all time, meaning the maximal solution’s domain might be a proper subset of ℝ.

These distinctions connect tightly to how orbits behave under uniqueness: solutions to an initial value problem cannot cross in phase space. With a locally Lipschitz vector field V, each initial condition x0 generates a unique maximal solution α(t), and the “no-crossing” rule implies that if a trajectory ever revisits a point, it must be a fixed point or a periodic orbit. For periodic solutions, there is a minimal period (unlike fixed points, where any T works because the solution never changes). This classification—injective trajectories, fixed points, and periodic orbits—organizes the face portrait into a small set of geometric patterns.

To make the ideas concrete, the discussion turns to a pendulum-type equation: x¨ = −sin(x). Converting it to a first-order system by setting x1 = x and x2 = x˙ yields x1˙ = x2 and x2˙ = −sin(x1), so the vector field in ℝ² is V(x1, x2) = (x2, −sin(x1)). Instead of sketching V directly, a key trick identifies a conserved quantity. If there exists a function f(x1, x2) whose value stays constant along solutions, then trajectories must lie on contour lines of f.

The constancy condition is derived using the chain rule: requiring d/dt f(α(t)) = 0 for all t is equivalent to ∇f(α(t)) · α˙(t) = 0. Since α˙(t) = V(α(t)), this becomes the geometric requirement that ∇f is perpendicular to V everywhere. A suitable choice is f(x1, x2) = (1/2)x2² − cos(x1), whose gradient is (sin(x1), x2). This gradient is perpendicular to V, so f remains constant along trajectories. As a result, contour plots of f immediately reveal the phase portrait: fixed points occur where ∇f = 0, which forces x2 = 0 and sin(x1) = 0, giving x1 = kπ for integers k. The pendulum’s “normal” periodic motion appears as closed contour loops around the stable equilibrium points, while the equilibria at the top position (near the upside-down pendulum) also show up as fixed points—typically unstable even though they still satisfy the differential equation.

Finally, the conserved-energy picture explains the third category: trajectories with sufficiently high or low x2 correspond to motion that does not settle into the closed periodic loops, producing injective orbits that keep moving without repeating. The fixed points can also be stable or unstable depending on what happens when initial conditions are slightly perturbed, a topic saved for the next step via local linearization.

Cornell Notes

With a locally Lipschitz vector field V, every initial condition generates a unique maximal solution α(t), and orbits cannot cross. Three orbit types follow from uniqueness: fixed points where V(x*) = 0 (constant solutions), periodic solutions where α(t + T) = α(t) for some T (closed orbits with a minimal period), and injective non-repeating solutions (which may fail to exist for all time). For the pendulum equation x¨ = −sin(x), rewriting it as a first-order system produces V(x1, x2) = (x2, −sin(x1)). A conserved quantity f(x1, x2) = (1/2)x2² − cos(x1) satisfies ∇f ⟂ V, so f stays constant along solutions. Therefore, contour lines of f directly produce the phase portrait, including fixed points at (kπ, 0) and periodic loops around the stable equilibria.

Why does a fixed point correspond to a constant solution for all time?

A fixed point x* is defined by V(x*) = 0. If α(t) = x* for every t, then α˙(t) = 0. But the differential equation requires α˙(t) = V(α(t)) = V(x*) = 0, so the constant function satisfies the system for all t. Geometrically, the orbit is just the single point x* in the phase space.

What forces a trajectory to be either injective, periodic, or a fixed point?

With V locally Lipschitz, the initial value problem has a unique maximal solution for each starting point x0. Uniqueness implies trajectories cannot cross in phase space. If a solution ever revisits the same point in the domain D, then from that revisit onward the solution must coincide with the previously generated one; that forces either a fixed point (stays forever) or a periodic orbit (repeats after some time). If no point is revisited, the orbit is injective (non-repeating).

How does the “conserved quantity” trick produce the phase portrait for the pendulum system?

The method seeks a function f(x1, x2) whose value stays constant along solutions: f(α(t)) = constant. Differentiating gives d/dt f(α(t)) = ∇f(α(t)) · α˙(t). Since α˙(t) = V(α(t)), constancy for all t is equivalent to ∇f ⟂ V along trajectories. Choosing f(x1, x2) = (1/2)x2² − cos(x1) yields ∇f = (sin(x1), x2), which is perpendicular to V(x1, x2) = (x2, −sin(x1)). Thus solutions lie on contour lines of f, and those contours become the phase portrait.

Where are the fixed points for the pendulum equation x¨ = −sin(x)?

Fixed points occur where V = 0, equivalently where ∇f = 0 in the conserved-quantity setup. Here V(x1, x2) = (x2, −sin(x1)), so V = 0 forces x2 = 0 and sin(x1) = 0. That gives x1 = kπ for integers k. In phase space, the equilibria are (kπ, 0), repeating infinitely along the x1-axis.

Why do closed contour loops correspond to periodic motion, while other contours correspond to injective motion?

Because f is constant along trajectories, each solution stays on one contour line of f. Closed contours form loops in phase space, so the state returns to earlier positions and the motion repeats—this is periodic behavior. Contours that do not close correspond to trajectories that keep moving without repeating a point, producing injective orbits (non-repeating motion).

Review Questions

  1. What is the precise condition for a solution to be periodic, and how does it differ from a fixed point?
  2. How does local Lipschitz continuity of V connect to the “no-crossing” property of orbits?
  3. For the pendulum system, verify that the chosen f(x1, x2) = (1/2)x2² − cos(x1) remains constant by checking the perpendicularity condition ∇f ⟂ V.

Key Points

  1. 1

    Fixed points are exactly the states where the vector field vanishes (V(x*) = 0), producing constant solutions α(t) = x* for all t.

  2. 2

    Periodic solutions satisfy α(t + T) = α(t) for every t; their orbits are closed curves, and they have a minimal period (unlike fixed points).

  3. 3

    Uniqueness from a locally Lipschitz vector field prevents orbit crossing; revisiting a point forces the orbit to be periodic or a fixed point.

  4. 4

    For x¨ = −sin(x), rewriting as x1˙ = x2 and x2˙ = −sin(x1) yields a vector field V(x1, x2) = (x2, −sin(x1)).

  5. 5

    A conserved quantity f(x1, x2) = (1/2)x2² − cos(x1) satisfies ∇f ⟂ V, so f is constant along solutions and contour lines give the phase portrait.

  6. 6

    Fixed points for the pendulum occur at (kπ, 0) because x2 = 0 and sin(x1) = 0.

  7. 7

    Closed contour loops correspond to periodic pendulum motion, while non-closed contours correspond to injective (non-repeating) trajectories.

Highlights

Fixed points and periodic orbits are the only ways a trajectory can revisit a point in phase space under uniqueness.
Finding f with ∇f perpendicular to V turns phase-portrait sketching into contour plotting.
For the pendulum, f(x1, x2) = (1/2)x2² − cos(x1) produces fixed points at (kπ, 0) and closed loops for normal oscillations.
The upside-down equilibrium also appears as a fixed point, even though it is typically unstable under perturbations.

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